Question

A car travels with the velocity 10m/s and accelerates 5 m/s 2 .calculate the final velocity when it has travelled 30m.

Answer 1

2as=v^2-u^2

2×5×30=v^2-10^2

300 = v^2-100

300+100=v^2

400=v^2

v=√400

v=20

please follow me

Answer 2

Given :

• Initial Velocity = 10 m/s
• Acceleration = 5 m/s²
• Distance travelled = 30 m

To Find :

• Final Velocity = ?

Solution :

★ By using third equation of motion we get :

• v² = u² + 2as

where,

• v is Final Velocity
• u is Initial Velocity
• a is acceleration
• s is distance travelled

★ Now,plug in the given values in above equation of motion :

→ v² = (10)² + 2 × 5 × 30

→ v² = 100 + 10 × 30

→ v² = 100 + 300

→ v² = 400

→ v = √400

→ v = 20 m/s

• Hence,the final velocity of the car is 20 m/s.

★ Three equations of motion :

• v = u + at
• s = ut + ½ at²
• v² = u² + 2as