A car travels with uniform velocity of 25 m s^-1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find: (i) The distance which the car travels before the brakes are applied, (ii) Retardation and (iii) The distance travelled by the car after applying the brakes.
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Answer: u = 25 ; t = 10
so a = u/t
a = 25/10
a= 2.5m/square
Explanation: distance before brake = 25*5=125 m
Distance after brakes = S = u×t - (1/2)×a×t2 = 25×10 - (1/2)×2.5×100 = 125 m
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