Question

A car travels with uniform velocity of 25 metre per second for 5 seconds The break are applied and the car is uniformly retested and come to rest in 10 second
1) The distance which the car travel before applied the brakes
2)retardation
3 )distance travel by car after applying brake

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Answer 1

distance travel by car after applying brakes

Answer 2

hello,
given v=25m/s,t=5s
(1)distance travelled before breaks(S)
we know that S=vt
S=25×5
S=125m
(2)=retardation or negative acceleration(-a)
given that after applying breaks it comes to rest after 10s
we know that (v-u)/t=a  (final velocity-initial velocity)/time=acceleration
here,v=0m/s as car comes to rest and u=25m/s t=10s
0-25/10=(-2.5m/s²) is acceleration therefore retardation will 25m/s²
(3)distance travelled by car after applying breaks 
we know the equations of motion,here we will use 3rd equation
2aS=v²-u²
here a we have found out -2.5m/s² v=0m/s u=25m/s
2·-2.5·S=0²-25²
-5S=0-625
-5S=-625
5S=625
S=125m
after apllying brakes it will travel 125m