Question

A car travels with velocity 2.24 kilometre per hour in first minutes, 3.60 kilometre per hour ii n second minute and with 5.18 kilometre per hour in third minute. Calculate the average velocity in these three minutes​

Answer 1

Answer:

3.67 km/h

Explanation:

Given

Velocity of car in 1st minute

= 2.24 km/h

Velocity of car in 2nd minute

= 3.60 km/h

Velocity of car in 3rd minute

= 5.18 km/h

To Find

Average Velocity of the car

Now

$Distance \: travelled \: in \: first \\ minute(s_{1}) = v_{1} \times t_{1} \\ = > s_{1} = 2.24 \times \frac{1}{60} \\ = > \boxed{s_{1} = \frac{2.24}{60}km } \\ Distance \: travelled \: in \: second \\ minute(s_{2}) = v_{2} \times t_{2} \\ = > s_{2} = 3.60 \times \frac{1}{60} \\ = > \boxed{s_{2} = \frac{3.60}{60}km } \\ Distance \: travelled \: in \: third \\ minute(s_{3}) = v_{3} \times t_{3} \\ = > s_{3} = 5.18 \times \frac{1}{60} \\ = > \boxed{s_{3} = \frac{5.18}{60}km }$

Now we have all three distances

$Total \: Distance(s) = s_{1 } + s_{2 } + s_{3} \\ s = \frac{2.24}{60} + \frac{3.60}{60} + \frac{5.18}{60} \\ \boxed{s = \frac{11.02}{60} km}$

$Total \: Time \: Taken(t) = t_{1 } + t_{2 } + t_{3} \\ = > t = 1 + 1 + 1 \\ = > \boxed{t = 3 \: minutes}$

$Average \: Velocity = \frac{Total \: Distance(s)}{Total \:Time \: Taken(t) } \\ = > Average \: Velocity = \frac{11.02}{ \cancel60} \times \frac{ \cancel20}{1} \\ = >Average \: Velocity = \frac{11.02}{3} \\ = > \boxed{Average \: Velocity = 3.67 \: km/h}$

Therefore

Average velocity of the car will be 3.67 kilometre per hour.

Answer 2

ɢᴏᴏᴅ ᴍᴏʀɴɪɴɢ ᴅᴇᴀʀ

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ᴀɴsᴡᴇʀs–

3. 67 ᴋᴍ/ʜ

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ɢɪᴠᴇɴ-

ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴄᴀʀ ɪɴ 1sᴛ ᴍɪɴ =2.24 ᴋᴍ/ʜ

ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴄᴀʀ ɪɴ 2ɴᴅ ᴍɪɴ =3.60 ᴋᴍ/ʜ

ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴄᴀʀ ɪɴ 3ʀᴅ ᴍɪɴ =5.18 ᴋᴍ/ʜ

ғɪɴᴅ - ᴀᴠɢ ᴠᴇʟᴏᴄɪᴛʏ ᴏғ ᴄᴀʀ

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ᴇxᴘʟᴀɴᴀᴛɪᴏɴ —

ᴛᴏᴛᴀʟ ᴅɪsᴛᴀɴᴄᴇ ʙʏ ᴄᴀʀ = s1 + s2 + s3

=>s = 2. 24/60 +3. 60/60 +5. 18/60

=>s = 11. 02/60 ᴋᴍ

ᴛᴏᴛᴀʟ ᴛɪᴍᴇ (ᴛ) ɪs 3 ᴍɪɴ

ᴛʜᴇʀᴇғᴏʀᴇ, ᴀᴠɢ ᴠᴇʟᴏᴄɪᴛʏ = s/ᴛ

=> <ᴠ> = 11. 02/(60*3) km/min

=> <ᴠ> = 3. 67 ᴋᴍ/ʜ

ᴛʜᴇʀᴇғᴏʀᴇ ᴀᴠɢ ᴠᴇʟᴏᴄɪᴛʏ ɪs 3.67 ᴋᴍ/ʜ

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