A car traves 100 k m east and then 100 km south finally its come back to the starting point by the south east route throughout the joureny the speed is constant at 60 kmh the average velocity for the whole journey if time taken is 3.3 hours is
Answers
Answered by
22
Read the question till end.
The question asks average velocity.
The car reaches the same point from where it had started its journey.
So displacement = 0
velocity = displacement/time = 0/time = 0
Velocity is 0.
The question asks average velocity.
The car reaches the same point from where it had started its journey.
So displacement = 0
velocity = displacement/time = 0/time = 0
Velocity is 0.
Answered by
27
Answer = 0 m/s
Explanation:
Given,
Car travels in East = 100 km
Again, in South = 100 km
Distance Travelled:
⇒ 3.3 × 60
⇒ 33 × 6 = 198 km
Now,
It comes back to the starting point by the south east route at the constant speed of 60 km/h
Again,
The car reaches the same point from where it had started its journey.
Hence, Displacement = 0
Velocity Given as,
⇒ Displacement/Time
⇒ 0/3.3
⇒ 0
Hence, The required Velocity is 0 m/s.
Hope It Helps!
Explanation:
Given,
Car travels in East = 100 km
Again, in South = 100 km
Distance Travelled:
⇒ 3.3 × 60
⇒ 33 × 6 = 198 km
Now,
It comes back to the starting point by the south east route at the constant speed of 60 km/h
Again,
The car reaches the same point from where it had started its journey.
Hence, Displacement = 0
Velocity Given as,
⇒ Displacement/Time
⇒ 0/3.3
⇒ 0
Hence, The required Velocity is 0 m/s.
Hope It Helps!
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