A car uniform acceleration change it velocity 30 km/hr to 60 km/h in 15 sec Calculate the amount of acceleration of the Car and the distance travelled by car during this period
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Answer:
acceleration= 7.2 m/s^2
distance = 187.5
Step-by-step explanation:
acceleration - Let's assume its 'a'.
a= (final velocity-initial velocity)/time taken
a= (60km/hr-30km/hr)/15sec
a=(216-108)/15 [conversion of km/hr to m/s]
a=7.2 m/s^2
Assume distance as 's'
v^2=u^2+2as
3600=900 + 2(7.2)(s)
2700= 14.4s
2700/14.4 = s
s = 187.5
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