Question

A car uniform acceleration change
it velocity
38 km/hr to 60 km/h in 15 sec
Calculate the amount of acceleration of the
Car and the distance travelled by car
during
this period​

Answer 1

Gɪᴠᴇɴ

Initial velocity of car = 38 km/h

Final velocity of car = 60 km/h

Time taken = 15 seconds

Tᴏ ꜰɪɴᴅ

Acceleration of car & distance travelled by car.

Sᴏʟᴜᴛɪᴏɴ ➀ 

Here, change in velocity is given by,

⇒ v - u [Final velocity - Initial velocity]

⇒ (60 - 38) km/h

⇒ 22 km/h

⇒ (22 × 1000)/3600 m/s

⇒ (22 × 5)/18 m/s

⇒ 110/18 m/s

⇒ 6.11 m/s

We know that,

⇾ a = (v - u)/t

⇾ a = 6.11/15

⇾ a = 0.41 m/s²

Tʜᴇʀᴇꜰᴏʀᴇ,

Acceleration of car = 0.41 m/s²

Sᴏʟᴜᴛɪᴏɴ ➁

Here, initial velocity = 38 km/h

⇒ u = 38 × (5/18) m/s

⇒ u = 10.56 m/s

We know that,

⇒ s = ut + ½at²

⇒ s = 10.56(15) + ½(0.41 × 15²)

⇒ s = 158.4 + ½(0.41 × 225)

⇒ s = 158.4 + ½(92.25)

⇒ s = 158.4 + 46.125

⇒ s = 204.525 m

Tʜᴇʀᴇꜰᴏʀᴇ,

Distance travelled by car = 204.525 m

Answer 2

Aɴꜱᴡᴇʀ

➜ The acceleration of the body = 0.14 m/s²

➜ The distance travelled by the body = 204.525 m

_________________

Gɪᴠᴇɴ

➳ Intial velocity (u) = 38km/h = 1.05m/s

➳ Final velocity (v) = 60km/h = 16.6m/s

➳ Time (t) = 15 seconds

_________________

Tᴏ ꜰɪɴᴅ

☆ The acceleration of the car

☆ Distance travelled by it

_________________

Sᴛᴇᴘꜱ

➤ To find the acceleration we can use the normal formula to find accelerataion

Substituting the given values

$\large \tt \leadsto{}a = \dfrac{v - u}{t} \\ \\ \large \tt \leadsto{}a = \frac{ \frac{(38 - 60)1000}{3600} }{15} \\ \\ \large \tt \leadsto{}a = \frac{6.11}{15} \\ \\ \large \pink{\tt \leadsto{}a = 0.41m/ {s}^{2} }$

❍ So then we can find the Distance travelled by the body can be found by the second equation of motion, that is

$\large{ \underline{ \boxed{ \sf{s = ut + \frac{1}{2} a {t}^{2} }}}}$

Substituting the given values,

$\large \tt \dashrightarrow{}s = 10.56\times 15 + \dfrac{1}{2} \times 0.41 \times {15}^{2} \\ \\ \large \tt \dashrightarrow158.4 + \frac{1}{2} (92.25) \\ \\ \large \tt \dashrightarrow{}158.4 + 46.125 \\ \\ \large \tt \pink {\dashrightarrow{}s =204.525 \: m}$

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