Question

A car uniform aceleration change it velocity 30 km/ hr to 60 km/hr in 15 sec Calculate the amonunt of acceleration of the Car and the distance travelled by car​

Answer 1

Given that :

Final velocity (v) = 60km/h = 60×1000/3600 m/sec

=> Final velocity (v) = 50/3 m/sec

Initial velocity (u) = 30km/h = 30×5/18m/sec = 25/3m/sec

And time (t) = 15 sec

Now, as we know that :

v = u + at where, a = Acceleration

=> 50/3 = 25/3 + a×15

=> 25/3 = 15a

=> a = 5/9 m/sec^2

As we know that :

${v}^{2} = {u}^{2} + 2as \\ \\ = > { (\frac{50}{3}) }^{2} = {( \frac{25}{3}) }^{2} + 2 \times \frac{5}{9} \times s \\ \\ = > \frac{2500}{9} = \frac{625}{9} + \frac{10}{9} \times s \\ \\ = > \frac{2500 - 625}{9} = \frac{10s}{9} \\ \\ = > \frac{1875}{9} = \frac{10s}{9} \\ \\ = > s = \frac{1875}{10} = \frac{375}{2} = 187.5 \: m$

I hope it will be helpful for you ☺