Question

a car uniform motion travels 50 min in 20s
what is its speed ?
how does this travels in
​

Answer 1

• Speed = distance traveled/ time taken

= 500 m / 20 sec = 25 m/s

• Thus the car travels 25 meters in one second.

In 5 seconds the car will travel a distance of 5 × 25 = 125 meters.

Time needed to travel 90 meters will be

= distance / speed

= distance / speed= 90 / 25 sec

= distance / speed= 90 / 25 sec= 3.60 sec

More Info:-

we have,

car travelled 500 m in 20 seconds

Thus,speed =

$\frac{distance}{time} = \frac{500}{20} = 25m {s}^{ - 1}$

Now, distance travelled in 1 second = 25 × 1 = 25m.

Distance travelled in 5 second = 25 × 5 = 135 m.

Time taken to cover 90 m = 90/25 = 3.6 seconds.

Basics formulas used here are :-

$\begin{gathered}speed = \frac{distnce}{time } \\ distance = speed \times time \\ time = \frac{distance}{speed} \end{gathered}$

Answer 2

Answer:

we have,

car travelled 50 min in 20 sec

thus the formula is

$thus \: the \: formula \: is \: = \: \frac{distance}{time}$

$= \: \frac{50}{20} = 2.5m {s}^{1}$

now distance travelled in 1sec.

= 2.5 × 1 = 2.5m

distance travelled in 5sec = 2.5 × 5 = 12.5 m

$time \: travelled \: to \: cover \: 90 m \: = \frac{90}{2.5} = \: 36sec$