Question

)
A car uses a convex mirror of curvatu
1.2 m as its rear-view mirror. A minibus
of cross section 2.2 m x 2.2 m is 6.6 m
away from the mirror. Estimate the image
size.​

Answer 1

Answer:

image formed will virtual and erect.

hope it helps dear..

Answer 2

Answer:

The image size of the minibus is of cross-section 0.18 m x 0.18 m.

Explanation:

Given data:

R = 1.2 m

Size of object/minibus, ho = 2.2 m

Distance of the object/minibus, u = 6.6 m

To find: The image size of the minibus

We know that the mirror given is a convex mirror so the image formed will be virtual and erect. The focal length “f”, the image size “hi” and the image distance “v” will be negative.

We have,

R = 1.2 m

∴ f = - R/2 = - 1.2/2 = -0.6 m

The mirror equation gives us,

1/f = 1/u + 1/v

Or, -1/0.6 = 1/6.6 + (-1/v)

Or, 1/v = 1/6.6 + 1/0.6

Or, v = (6.6 * 0.6) / (6.6 + 0.6)

Or, v = (6.6 * 0.6) / 7.2 = 0.55 m

We know,

Magnification = v/u = -hi/ho

∴ v/u = -hi/ho

Or, -hi = (v/u) * ho = (0.55/6.6) * 2.2 = 0.18

Or, hi = -0.18 m

∴ The image size is 0.18 m.