A car waiting at a traffic signal as it turn green the car starts a head with a constant acceleration of 3 m/s 2/at the same time a bus traveling with a constant speed of 20 m/s overtakes and pass the car what will the velocity of the car at that time nd how far beyond its starting point will the car over takes the bus ???
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40
Distance travelled by truck in time t moving with uniform velocity 10 m/s
distance = velocity ×time =
d = 10 t
Distance should be equal to the car moving with acceleration 2 m/s2 in time t.
s = ut + 1/2at2
as car start from rest then initial velocity is zero.
10t = 0 + 1/2×2×t2
t = 10 s
distnace travelled = 10×10 = 100 m
velocity of the car after 10 s.
v = u + at
v = 0+2×10
v = 20 m/s
distance = velocity ×time =
d = 10 t
Distance should be equal to the car moving with acceleration 2 m/s2 in time t.
s = ut + 1/2at2
as car start from rest then initial velocity is zero.
10t = 0 + 1/2×2×t2
t = 10 s
distnace travelled = 10×10 = 100 m
velocity of the car after 10 s.
v = u + at
v = 0+2×10
v = 20 m/s
chandan3129:
is method s digit ko dekh lena
but ut ???? s=vit + 1/2 at2
vi is the initial velocity but ut ???
Answered by
6
Answer:Distance travelled by truck in time t moving with uniform velocity 10 m/s
distance = velocity ×time =
d = 10 t
Distance should be equal to the car moving with acceleration 2 m/s2 in time t.
s = ut + 1/2at2
as car start from rest then initial velocity is zero.
10t = 0 + 1/2×2×t2
t = 10 s
distnace travelled = 10×10 = 100 m
velocity of the car after 10 s.
v = u + at
v = 0+2×10
v = 20 m/s
Explanation:
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