A car waiting at a traffic signal. As it turns green the car starts ahead with a constant acceleration of 3 m/s. at the same time a bus travelling with constant speed of 20m/s overtakes and passes the car.(a)How far beyond its starting point will the car overtakes the bus?(b)What will be the velocity of car at that time?
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Answer:Distance travelled by truck in time t moving with uniform velocity 10 m/s
distance = velocity ×time =
d = 10 t
Distance should be equal to the car moving with acceleration 2 m/s2 in time t.
s = ut + 1/2at2
as car start from rest then initial velocity is zero.
10t = 0 + 1/2×2×t2
t = 10 s
distnace travelled = 10×10 = 100 m
velocity of the car after 10 s.
v = u + at
v = 0+2×10
v = 20 m/s
Explanation:
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