a car was at rest 10m/s2 and within 5 second it attains a velocity find its final velocity and distance travelled
Answers
Answered by
1
Answer:
Given,
a=10m/s²
u=0m/s
t=5sec
From 2nd equation of motion,
S=ut+1/2at²
S=0×5+1/2×10×5×5
S=0+125
S=125m
Answered by
5
Answer:
u =0
v= 10m/s2
t=5s
v=u+at
10=0+a x 5
10=a x 5
a x 5 = 10
a =2
By the second equation of motion
S=ut + 1/2at^2
=> S = 0 x 10 + 2 x 2 x 5^2
=>S = 0+100
=> S =100 m
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