Math, asked by mazinazad, 1 month ago

a car was at rest 10m/s2 and within 5 second it attains a velocity find its final velocity and distance travelled

Answers

Answered by rajanichowdhary058
1

Answer:

Given,

a=10m/s²

u=0m/s

t=5sec

From 2nd equation of motion,

S=ut+1/2at²

S=0×5+1/2×10×5×5

S=0+125

S=125m

Answered by TANVEERJAMAN
5

Answer:

u =0

v= 10m/s2

t=5s

v=u+at

10=0+a x 5

10=a x 5

a x 5 = 10

a =2

By the second equation of motion

S=ut + 1/2at^2

=> S = 0 x 10 + 2 x 2 x 5^2

=>S = 0+100

=> S =100 m

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