a car was bought in 2009 for $120,000 in 2010 its value decreased by 20%.in 2011 its value decreased by 10%.find the value of the. car in the end of2011
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Answered by
19
Step-by-step explanation:
The value of the car at the end of 2010
=$120000(80/100)
=$96000
The value of the car at the end of 2011
=$96000(90/100)
=$86400
Answered by
3
C. P of car 2009 = 120000
C. P of car after 20% decreased = 20/100x120000
=24000
Nw price of car in after reducing 10% in 2011= 10/100x24000
= ₹2400
C. P of car after 20% decreased = 20/100x120000
=24000
Nw price of car in after reducing 10% in 2011= 10/100x24000
= ₹2400
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