a car was brought in 2009 for $120000.in 2010,its value decreased by 20% .in 2011 its value decreased by 10% of its value in 2010 .find the value of the car at the end of 2011.
Answers
Answered by
44
This is the case % decrease
120000*80/100*90/100
=12*80*90
=7200*12
=72000+ 14400
=86400 rs
Hope u understand
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Answered by
54
Price of car in 2009 = $120000
Value decreased by 20 % in 2010
⇒ Price of car in 2010 = $120000 - (20% of $120000)
= $120000 - ( (20/100) × 120000 )
= $120000 - $24000 = $96000
Value again decreased by 10 % in 2011
⇒ Price of car in 2011= $96000 - (10% of $96000)
= 96000 - ((10/100) × 96000 )
= 96000 - 9600 = $86400
So value of car at end of 2011 is $86400
thank u so much
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