Question

A car was going from city P to city Q. However, engine malfunction at a certain point and the car travelled at 5/6 of original speed and hence was 1 hour late. However if the engine had malfunctioned 300 km earlier, it would have been late by 2 hours. Find the speed of the car​

Answer 1

here is less mathematical approach.

let the two end points between which this train is running be A and B. Also suppose that accident occurs at C which is at a distance of 50km from A. thus we have

A---------50km----------C----------------------------B 1)

Time taken to travel the distance after the accident i.e. CB is 35 minutes more than the usual time.

now, if the accident were to occur at 24 km farther, then train would have reached only 25 minutes late. i.e.

A--------50 km----------C---------24--------D---------------B 2)

if we look at the situation depicted in 1) and 2) we will see that 10 minute difference in time is occurring because of this 24 Km. which is traveled by its usual speed (=x) in the later case. thus we have

- =

- =

solving this we get x= 48km/h

Answer 2

Let speed of the slower train is x km/hr, then speed of faster is (x+10) kmph.

Let faster train takes t hours to cover the distance 300 km, then slower one takes (t+8) hours.

Distance is same. So

x/(x+10) = t/(t+8)

Solve, 4x = 5t

Hope it's helpful dear...............