Question

A car was moving at 36 km/h ,when the driver applied the brakes .The retardation produced by the brakes was 1m/s. Find the distance the car travelled before stopping.

Answer 1

Answer:

GIVEN

SPEED OF CAR (U) = 36KM/H = 10M/S

acceleration (A) = –1m/s²

Final velocity(V) =0

TO FIND

distance before stopping (S)

SOLUTION

WE KNOW THAT

V² –U²/2A = S (3RD EQUATION OF MOTION)

THUS ON EQUATING VALUES WE GET

–100/-2 = S

S= 50

hence 50m distance is travelled by car before stopping

Answer 2

Answer:

The car will cover 50 m of distance before stopping.

Explanation:

We have to use the formula v^2=u^2-2as as there is a retardation.

V=0

U=10m/s

A=1 m/s

s=?

Hope you got your answer mate.