A car was moving at a rate of 18km/hr when the brakes were applied. if it comes to rest after traveling a distance of 5m calculate the retardation produced in the car
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18kmph=18×5/18m/s=5m/s
v=0
d=5
v^2 + u^2 = 2as
0 - 25 = 2(a)(5)
a= -25/10= -2.5 m/s^2
pragati369:
t is not equal to 5m because 5 m is the distance. please correct it.
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here is the explaination
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