A car was moving at a velocity of 20m/s on a levelled road.The driver pressed the accelerator of the car and within 5 seconds the velocity of the car reached 80m/s. If the kinetic energy possessed by the car is 2100 kJ, calculate the mass of the car. What will be the kinetic energy possessed by the car when it eventually comes to rest?
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Given
u(initial velocity) = 20m/s
v(final velocity) = 80m/s
K.E = 2100kj
We know that
K.E = 1/2mv^2
2100 = 1/2 x m x 80 x 80
m= 2100 x 2/80 x 80
= 0.65kg
Mass = 0.65kg
Kinetic energy when the body comes to rest = 0
Because when the body comes to rest, its final velocity becomes zero it means complete kinetic energy is 0
u(initial velocity) = 20m/s
v(final velocity) = 80m/s
K.E = 2100kj
We know that
K.E = 1/2mv^2
2100 = 1/2 x m x 80 x 80
m= 2100 x 2/80 x 80
= 0.65kg
Mass = 0.65kg
Kinetic energy when the body comes to rest = 0
Because when the body comes to rest, its final velocity becomes zero it means complete kinetic energy is 0
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