Question

. A car was moving with a velocity of 18 m/s. Brakes are applied and it comes to rest in 5 s. Calculate the acceleration and the distance traveled by the car in 5 s.

Answer 1

Step-by-step explanation:

Initial velocity(u) = 18 m/s

Final velocity (v) = 0 m/s

Time = 5s

So acceleration = v-u/t

= 0 m/s-18 m/s

= -18 m/s

Sorry I can't do the next problem.

Answer 2

Answer:

initial velocity (u) = 18m/s

final velocity (v) = 0m/s

time (t) = 5s

v = u+at

0 = 18 + 5a

5a = -18

a = -18/5 m/s∧2  (acceleration will be negative because due to the applying of  brakes it becomes retardation)

distance (s)= ut + 1/2at∧2

s = 18×5 - 18/5×1/2×25

s = 90 - 9/5×25

s = 90 - 45 = 45m

acceleration = -18/5 m/s∧2

distance = 45m

hope this helps.