Question

a car was moving with a velocity of 90 km per hour and the brakes were applied in the car stopped after 4 seconds calculate the distance travelled before the stop​

Answer 1

Answer:

v=u+at

90=0+4a

a=90/4=45/2=22.5

s=ut+1/2at²

s=0+1/2(22.5)(4)²

s=1/2x22.5x16

s=22.5x8

solve this u get urs answer perfectly