A car was moving with velocity 160 km/hr.If driver of the car wants to change (increase) its velocity from 160 km/hr to 200 km/hr in five minutes, Mass of the car is 800 kg. What force is applied to increase the speed ?
(ANSWER) :-
U = 160 km/hr. = 160×5/18 =400/9=44.44 m/s v=200 km /hr = 200×5/18=500/9 m/s=55.55 m/s t=5 min 5×60 = 300 s mass= 800 kg we know that, f=m×a a=(v-u)÷t (55.55-44.44)/300 11.11/300 = 0.037 a= 0.037 m/s^2 force = 800×0.037 =29.6 N
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