Question

A car was travelling at a speed of 10 m/s. After the brakes were applied, it start to decelerate at a rate of 2 m/s ² and finally came to rest. Find the distance traveled by the car before coming to rest.

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Answer 1

Solution :

Here, car is travelling at the speed of 10 m/s. So,

• initital speed of the car, u = 10 m/s

After the brakes were applied, it starts to decelerate at a rate of 2m/s². So,

• final speed of the car, v = 0 m/s
• retardation of the car, a = -2m/s²

Let's use the formula v² - u² = 2a.s.

Put the values of u, v and a in the formula.

=> v² - u² = 2as

=> (0)² - (10)² = 2(-2)s

=> -100 = -4s

=> s = 100/4

=> s = 25m

∴ The distance travelled by the car before coming to the rest is 25m.