Question

A car was travelling with a velocity of 10 m/s. If it change to 20 m/s with aceleration of 2 m/s² Find the distance travelled

Answer 1

Answer:

-5

Explanation:

uniform =10

velocity =20

acceleration =2

A= V-U/T

10-20=-10/2=-5

Answer 2

Given:-

•A car was traveling with a velocity of 10m/s.

•It change to 20m/s with acceleration of 2m/s^2.

To Find:-

•Find the distance travelled

Solution:-

we have,

• v = 20m/s
• u = 10m/s
• a = 2m/s^2

Using Formula:

$\: \: \sf \: {v}^{2} = {u}^{2} + 2as$

Now substitute the values,

$\: \: \sf \: {20}^{2} = {10}^{2} + 2 \times 2 \times s \\ \\ \: \: \sf \: 400 = 100 + 4s \\ \\ \: \: \sf \: 400 - 100 = 4s \\ \\ \: \: \sf \: 300 = 4s \\ \\ \: \: \sf \: s = \frac{400}{3} \\ \\ \: \: \sf \: s = 75m$

Hence, distance of a car is 75m.

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Here,

• v denotes final velocity
• u denotes inital velocity
• a denotes acceleration

Formulas:

• s =ut + 1/2at^2
• a = v-u/t
• v = u +at