Question

A car weighing 10,000 newtons is parked in a garage. Which statement is true about the forces acting on the car?

Answer 1

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Answer 2

Explanation:

GIVEN :-

Force , F = 10000 N.

Time , t = 10 seconds.

TO FIND :-

The change in momentum of a car , ∆p.

SOLUTION :-

As we know that the rate of change in momentum of any object is given by,

$\\ : \implies \displaystyle \sf \: \Delta p = m(v - u).$

Now, by using the second law of motion we have,

$: \implies \displaystyle \sf \: F = \frac{m(v - u)}{t}$

$: \implies \displaystyle \sf \:10000 \: kg.ms ^{ - 2} = \frac{m(v - u)}{10}$

$: \implies \displaystyle \sf \:10000 \: kg.ms ^{ - 2} \times 10s =m(v - u)$

$: \implies \displaystyle \sf \:100000 \: kg.ms ^{ - 2 + 1} =m(v - u)$

$: \implies \displaystyle \sf \:100000 \: kg.ms ^{ - 1} =m(v - u)$

$: \implies \displaystyle \sf \:100000 \: kg.ms ^{ - 1} =\Delta p$

$: \implies \underline{ \boxed{\displaystyle \sf \: change \: in \: momentum = 100000 \: kg.ms ^{ - 1}}}$