Question

A car weighing 100 kg is on a slope that makes an angle 30' with the horizontal. The components of car's weight parallel to the slopes is

Answer 1

The component of weight along the slope is:
$F_{x} =mgsin \beta \\ F_{x}=100\times\ 10\times sin30=500N$

Answer 2

Weight of the car = mg = 1000 N
If you draw the FBD, you will observe that the angle between the weight vector and the slope is 60°.
So the component of the car's weight parallel to the slope is 1000 cos 60°= 500N