A car weighing 1000 kg and traveling at 30 m/s stop at a distance of 50 m. what is the force exerted on it by breaker? what is work done also by the brakes?
Answers
Answered by
4
humass=1000kg
u=30m/s
v=0
s=50m
by 3rd equation of motion
v²-u²=2as
0-900=2*a*50
-900=100a
a=-9 m/s²
force = m*a
f= -9*1000
f= -9000 N
work done= F*s
=9000*50
=450000Joules
Hope it helps
u=30m/s
v=0
s=50m
by 3rd equation of motion
v²-u²=2as
0-900=2*a*50
-900=100a
a=-9 m/s²
force = m*a
f= -9*1000
f= -9000 N
work done= F*s
=9000*50
=450000Joules
Hope it helps
priyanshu1578:
but second answer is wrong
it may be
sorry for that brother
it may be
sorry for that brother
sorry for that brother
let me search for mistakes
bro check it now
now ok
mark as brainliest
Similar questions