Question

A car weighing 1000 kg is going up an incline with a slope of 2 in 25 at a
steady speed of 18 kmph. If g=10 ms-2 , the power of its engine is​

Answer 1

Answer:

The answer is 4000 W.

Explanation:

As the car is going up an incline with a slope of 2 in 25 at a steady speed of 18kmph.

Therefore the slope is tan(θ) = 2/25 = sin(θ) approximately.

Thus the force "F" = 1000 x 10 x  2/25  

And power = Fv = 10000 x 2/25 x 18 x 5/18

                        = 4000 W

Thus the power of engine is 4000 W.