Question

A car weighing 1000kg and travelling at 30m/s stop at a distance of 50m decelerating uniformly what is the work done by the brakes

Answer 1

Answer:

450000J

Explanation:

because, F=ma

but 2aS=v^2-u^2

2.a.50=0-900

a=-900/2.50

a=-9

-ve sign show deacceleration

therefore, F=m.a=1000×9=9000

work done=F.s=9000×50=45kJ

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