A car weighing 1200 kg is uniformly accelerated from rest and covers a distace of 40m in 5 sec. calculate the work done by car engine
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s =(1÷2)at^(2)
thus a=3.2
f= ma
thus f=5120N
work = F*s=204800 Nm
thus a=3.2
f= ma
thus f=5120N
work = F*s=204800 Nm
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