A car weighing 1200 kg is uniformly accelerated from rest and covers a distance of 40 my in 5. Calculate the work done by the engine of a car during this time. What is the final kinetic energy of the car ?
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w=f*s
w=mgh
w=1200*40*10
w=480000j
kinetic energy = 1/2mv^2
v square - u square =2gh
v square = 2gh. u=0
1/2*1200*2*10*40
600*2*10*40
1200*400
480000J
w=mgh
w=1200*40*10
w=480000j
kinetic energy = 1/2mv^2
v square - u square =2gh
v square = 2gh. u=0
1/2*1200*2*10*40
600*2*10*40
1200*400
480000J
amanmalik08:
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