Question

A car weighing 1600kg moving with a velocity of 30m/s retards uniformly thereby coming to rest in 20 second. calculate (i) initial momentum of car (ii) final momentum of car (iii) rate of change of momentum(iv) acceleration of car (v) magnitude of force applied
[ write given also and write formula]​

Answer 1

Answer:

initial momentum=1600kg*30m/s=48000kgm/s

final momentum=1600kg*0m/s=0kgm/s

rate of change of momentum=(final momentum-initial momentum/time)=(0-48000)/20s*kgm/s=-2400kgm/s²

so force=-2400N

and acceleration of car=(0-30/20)*m/s²=1.5m/s²

Answer 2

Answer:

Mark it as brainliest

Explanation:

Given, m=1600kg

u=30m/s

v=0m/s

t=20sec

i) p(initial) = mu

=1600(30)

=48000 kgm/s

ii) p(final) =mv

=1600(0)

=0kgm/s

iii)Rate of change in momentum

$=\frac{m(v - u)}{t}$

$= \frac{1600(0 - 30)}{20}$

=800(-30)

=-2400 kgm/s

$iv)a = \frac{v - u}{t}$

$= \frac{0 - 30}{20}$

$= \frac{ - 3}{2} {ms}^{ - 2}$

v) F=ma

$= 1600( \frac{ - 3}{2} )$

=800(-3)

=-2400N