A car weighing 1600kg moving with a velocity of 30m/s retards uniformly thereby coming to rest in 20 second. calculate (i) initial momentum of car (ii) final momentum of car (iii) rate of change of momentum(iv) acceleration of car (v) magnitude of force applied
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1
Answer:
(1) 1600*30
(2) 0
(3) p = mv, so dp/dt = m dv/dt = 1600*(0-30)/(20-0) = -2400 kg-m/s
(4) see (3)
(5) F = ma
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Answered by
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Explanation:
here,
mass=1600kg
v=30m/s
u=0
t=20seconds
so,
initial momentum of car,
1600×0=0
final momentum of car,
1600×30
48000kgm s
now,
rate of change of momentum,
m(v-u)/t
=(mv-mu)/t
=48000-0/20
=2400
a=v-u/t
a=30-0/20
a=1.5m/s²
F=ma
F=1600×1.5
F=2400N
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