Science, asked by Sudipta2006, 9 months ago

A car weighing 1600kg moving with a velocity of 30m/s retards uniformly thereby coming to rest in 20 second. calculate (i) initial momentum of car (ii) final momentum of car (iii) rate of change of momentum(iv) acceleration of car (v) magnitude of force applied ​

Answers

Answered by shainamorwal25
1

Answer:

(1) 1600*30

(2) 0

(3) p = mv, so dp/dt = m dv/dt = 1600*(0-30)/(20-0) = -2400 kg-m/s

(4) see (3)

(5) F = ma

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Answered by mahakpanjwani
3

Explanation:

here,

mass=1600kg

v=30m/s

u=0

t=20seconds

so,

initial momentum of car,

1600×0=0

final momentum of car,

1600×30

48000kgm s

now,

rate of change of momentum,

m(v-u)/t

=(mv-mu)/t

=48000-0/20

=2400

a=v-u/t

a=30-0/20

a=1.5m/s²

F=ma

F=1600×1.5

F=2400N

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