A car weighing 200 kg working against a resistive force of 200 N accelerates from rest to 20ms−1 in 10 sec. The work done by the engine will be (g =10ms
Answers
Answered by
0
Answer:
Given t=100mins=6000sec
v−u=at
20=a×6000
a=
6000
20
=0.00334m/s
2
F−500=ma
F=500+500×0.00334+1.66
=501.66N
Work done =F×displacemnt in 100mins
=501.66×(
2
1
at
2
)
=501.66×(
2
1
×0.00334×(6000)
2
=30096J
Explanation:
Similar questions