Question

a car weighing 2000kg accerelates from rest and covers a distance of 40 metre in 6 sec. calculate the work done

Answer 1

Hello Mate!

Work done = Force × height

= F × s

= ma × s

Now, u = 0, s = 40 and t = 6 s

s = ut + ½ at²

40 = (0)(6) + ½(a)(6)²

40 = 18a

2.2 m/s² = a

Hence, Work done = (2000)(2.2) N × 40 m

= 1,76,000 J

Have great future ahead!

Answer 2

In this question,
Weight of Car = 2000 kg
Now, We are required to find out
Acceleration,

S= ut + 1/2 at^2
=> 40 m = 0 + 1/2 a x 6 x 6
=> 40 m = 1/2 x a x 36
=> 40/18 m = a
=> a = 2.2 m/s^2

Now,

Work Done = mah
=> W = (2000 x 2.2) N x 40 m
=> W = 4400 N x 40 m
=> W = 176000 Nm
or
=> W = 176000 Joules



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