A car weighing 2000kg is accelerated from rest and covers a distance of 40m in 6sec. Calculate the work done by the car
Answers
Answered by
2
Mass= 2000kg
u= 0 m/sec
t= 6sec
S=40m
Using 2nd eq. of motion
s=ut+1/2at^2
40= 1/2a (6)^2 (u=0)
80=36a
a=80/36 = 20/9
Work done=F.S
=m.a.s
=2000 x 20/9 x 40
=1600000/9 J
Hope it helps!!
Answered by
4
m= 2000 kg
u=0 m/s
s= 40 m
t=6 sec
s = ut +1/2 at² (By second equation of motion)
40= 0(6)+1/2×a×6×6
40 =a×18
a= 20/9 m/s²
F = ma
F= 2000× 20/9
F=40000/9 Newton
W = F× s
W = 40000/9 × 40
W = 1600000/9 = 177777.78 J
Hope this helps.
Don't forget to mark as Brainliest..
u=0 m/s
s= 40 m
t=6 sec
s = ut +1/2 at² (By second equation of motion)
40= 0(6)+1/2×a×6×6
40 =a×18
a= 20/9 m/s²
F = ma
F= 2000× 20/9
F=40000/9 Newton
W = F× s
W = 40000/9 × 40
W = 1600000/9 = 177777.78 J
Hope this helps.
Don't forget to mark as Brainliest..
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