Physics, asked by ratnakaraner, 1 year ago

A car weighing 2000kg is accelerated from rest and covers a distance of 40m in 6sec. Calculate the work done by the car

Answers

Answered by Superprodigy
2

Mass= 2000kg

u= 0 m/sec

t= 6sec

S=40m

Using 2nd eq. of motion

s=ut+1/2at^2

40= 1/2a (6)^2 (u=0)

80=36a

a=80/36 = 20/9

Work done=F.S

=m.a.s

=2000 x 20/9 x 40

=1600000/9 J

Hope it helps!!

Answered by Aishwarya00001
4
m= 2000 kg

u=0 m/s

s= 40 m

t=6 sec

s = ut +1/2 at² (By second equation of motion)

40= 0(6)+1/2×a×6×6

40 =a×18

a= 20/9 m/s²

F = ma

F= 2000× 20/9

F=40000/9 Newton

W = F× s

W = 40000/9 × 40

W = 1600000/9 = 177777.78 J

Hope this helps.
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