Question

A car weighing 2500 kg starts from rest and acquires a speed of 72 km h' in 20 s. Find
i) the acceleration
ii) the force, and
iii) the distance covered in 20 s.
(Ans. i) 1 ms 2, ii) 2500 N, iii) 200 m)

Answer 1

Explanation:

M=2500kg

u= 0

v= 72*5/18= 20

t = 20 sec

1) acceleration = v-u/t

= 20-0/20= 1m/s

2) f=ma

= 2500*1

= 2500 N

3) v^2-u^2 = 2as

= 200^2 - 0^2 = 2s

= 400 =2s

= distance = 400/2 = 200 m

Answer 2

Explanation:

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