Question

a car weighing 500 kg moving against resistance of 500 Newton ,accelerates from rest to 20 metre per second in 100 M calculate the work done by the engine of a car

Answer 1

I hope you have understand everything

Answer 2

Work done, W = 50 kJ

Explanation:

It is given that,

Mass of the car, m = 500 kg

Frictional force, f = 500 N

Initial speed of the car, u = 0

Final speed of the car, v = 20 m/s

Distance covered, d = 100 m

Let a is the acceleration of the car. Using the third equation of motion to find it as :

$v^2-u^2=2ad$

$v^2=2ad$

$a=\dfrac{v^2}{2d}$

$a=\dfrac{(20)^2}{2\times 100}$

$a=2\ m/s^2$

Force due to motion,

F = ma

$F=500\ kg\times 2\ m/s^2=1000\ N$

Net force acting on the car,

F' = F - f

F' = 1000 - 500

F' = 500 N

Work done by the engine of a car is given by :

$W=F'\times d$

$W=500\ N\times 100\ m$

W = 50000 Joules

or

W = 50 kJ

So, the work done by the engine of a car is 50 kJ. Hence, this is the required solution.

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Work done

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