Question

A car weighing 500kg climbs up a hill of slope 1 in 49 with a velocity of 36 KMPH. If the frictional force is 50N,the power delivered by the engine


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Answer 1

Answer:

1500 watts.

Explanation:

work done = F x V

rest in derived in annex

Answer 2

Given: A car weighing 500kg climbs up a hill of slope 1 in 49 with a velocity of 36 KMPH. If the frictional force is 50N

To find: the power delivered by the engine

Solution: we are given that car is climbing on a hill on which frictional force is acting

So we can say that force acting on the car along the hill in a downward direction will be

F = mgsin¢ + Fs

Here m is mass of the car, ¢ is the angle of the hill, Fs is frictional force acting on it

We also know that P= FV

here P is power delivered by the engine of the car, F is force acting on it, V is velocity with which car is climbing

P = ( 500×10×1/50 + 50) 36×5/18

P= 1500Watt

Therefore, total Power delivered by the engine will be 1500Watt.