A car weighing 600 kg moving with a velocity 30 m/s retards uniformly coming to test in 20 seconds . Calculate
1) initial and final momentum of the car
2) rate of change of linear momentum of the car
3) acceleration of the car
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m=600kg
u=30m/s
v=0
t=20sec
1)
Pi=mu=600×30=18000kg m/s
Pf=mv=600×0=0
2)
rate of change in momentum=(Pf-Pi)÷t
=(0-18000)÷20
=-900kg m/s
3)
a=(v-u)/t= (0-30)/20=-1.5m/s^2
u=30m/s
v=0
t=20sec
1)
Pi=mu=600×30=18000kg m/s
Pf=mv=600×0=0
2)
rate of change in momentum=(Pf-Pi)÷t
=(0-18000)÷20
=-900kg m/s
3)
a=(v-u)/t= (0-30)/20=-1.5m/s^2
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