a car weighs 1000N is moving with velocity 30m/s and stops at a dist of 50m decelerating uniformly.what is the work done by brakes on it.also calculate the work done by the brakes.
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W=F * S
F=m*a
We know that
v^2-u^2=2as
0-(30)^2=2*a*50
-900=2*a*50
a=-900/100
a= - 10
W=F*S
W=1000*50
W=50000
W=50kj
F=m*a
We know that
v^2-u^2=2as
0-(30)^2=2*a*50
-900=2*a*50
a=-900/100
a= - 10
W=F*S
W=1000*50
W=50000
W=50kj
Srividyashivakumar:
fine
karnataka
and u
ok
oh surely
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