Question

A car weithting 1200kg is uniform accelerating fro rest and covers a distance of 40m in 5sec. calculate the work done by engine of car during this time. what is the final kinetic energy of the car?​

Answer 1

speed=dis/time=40/5=8m/sec
now v=5m/s
k=1/2mv²
=1/2*1200*25
=15000
=15joule