A car which cost ₹2,50,000 depreciates by 10% every year. What will the car be worth after the years?
Plzz I need answer and also a method plzz
Answers
Answered by
47
Solution:
By The Given Method,
Present value = ₹ 250000
Decrease in first year:
= 10%
= 10% of 250000
= 10/100 × 250000
= ₹25000
So,value after first year =
₹250000 - 25000 = ₹225000
Decrease in second year
= 10%
= 10% of 225000
= 10/100 × 225000
= ₹22500
Value after second year
= 225000 - 22500 = ₹202500
Hence , the car's value of two years is ₹202500.
By The Given Method,
Present value = ₹ 250000
Decrease in first year:
= 10%
= 10% of 250000
= 10/100 × 250000
= ₹25000
So,value after first year =
₹250000 - 25000 = ₹225000
Decrease in second year
= 10%
= 10% of 225000
= 10/100 × 225000
= ₹22500
Value after second year
= 225000 - 22500 = ₹202500
Hence , the car's value of two years is ₹202500.
Answered by
23
Q: A car which cost ₹2,50,000 depreciates by 10% every year. What will the car be worth after the two years?
Solution :-
Given
A car which cost ₹2,50,000 depreciates by 10% every year.
Decrease in first year = 10%
= 10% of 250000
= 0.1 × 250000
= ₹ 25000
Find the cost of car after one year :-
₹(250000 - 25000) = ₹ 225000
Decrease in second year = 10%
= 10% of 225000
= 0.1 × 225000
= ₹ 22500
Find the cost of car after second year :-
= ₹ (225000 - 22500) = ₹ 202500
Hence ,
The car be worth after the two years = ₹ 202500
Solution :-
Given
A car which cost ₹2,50,000 depreciates by 10% every year.
Decrease in first year = 10%
= 10% of 250000
= 0.1 × 250000
= ₹ 25000
Find the cost of car after one year :-
₹(250000 - 25000) = ₹ 225000
Decrease in second year = 10%
= 10% of 225000
= 0.1 × 225000
= ₹ 22500
Find the cost of car after second year :-
= ₹ (225000 - 22500) = ₹ 202500
Hence ,
The car be worth after the two years = ₹ 202500
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