Question

A car which costs Rs 2,50,000 depreciates by 10% every year. What will the car be worth
after 3 years?
plzz ans the question n wll definitely mark the correct answer brainliest( pls show working also)

Answer 1

Answer:

Decrease in first year = 10%

Decrease in first year = 10%= 10% of 250000

Decrease in first year = 10%= 10% of 250000= 0.1 × 250000

Decrease in first year = 10%= 10% of 250000= 0.1 × 250000= ₹ 25000

Decrease in first year = 10%= 10% of 250000= 0.1 × 250000= ₹ 25000Find the cost of car after one year :-

Decrease in first year = 10%= 10% of 250000= 0.1 × 250000= ₹ 25000Find the cost of car after one year :-₹(250000 - 25000) = ₹ 225000

Decrease in second year = 10%

Decrease in second year = 10%= 10% of 225000

Decrease in second year = 10%= 10% of 225000= 0.1 × 225000

Decrease in second year = 10%= 10% of 225000= 0.1 × 225000= ₹ 22500

Decrease in second year = 10%= 10% of 225000= 0.1 × 225000= ₹ 22500Find the cost of car after second year :-

Decrease in second year = 10%= 10% of 225000= 0.1 × 225000= ₹ 22500Find the cost of car after second year :-= ₹ (225000 - 22500) = ₹ 202500

Hence,

The car be worth after the two years

= ₹ 202500

Hopes it help you❤️❤️

Answer 2

Answer: Hope this will be helpful.