Question

A car which is traveling at a velocity of 15 m/s undergoes an acceleration of 6.5 m/s2 over a distance of 340 m. How fast is it going after that acceleration? SHOW ALL WORK!

Answer 1

Given:-

• Initial velocity (u) = 15m/s

• Acceleration (a) = 6.5m/s²

• Distance (s) = 340m

To Find:-

• Final velocity of the car (v).

Solution:-

By using 3rd equation of motion

→ v² = u² +2as

Substitute the value we get

→ v² = 15² + 2×6.5×340

→ v² = 225 + 6.5×170

→ v² = 225 + 1105

→ v² = 1330

→ v = √1330

→ v = 34.46m/s

∴ The final velocity of the car is 34.46m/s.