a car which states from rest has an acceleration a for some time, then it decelerates, till it comes to rest. the magnitude of deceleration is also a. the maximum distance travelled by the car in time T is (T = time of whole travel)
a. aT^2
b. 2aT^2
c. 1/2aT^2
d. 1/4aT^2
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Answer:
initially car is at rest so
u=0
max velocity attentd by car ,time for max velo =T/2
v=0+aT/2=aT/2
distance covered by car during acc.
s1=0+(a(T/2)²)/2=aT²/8
distance covered during retardation
s2=aT/2(T/2)-1/2 a(T/2)²
=aT²/4-aT²/8
total distance covered by car,
s1+s2= aT²/8+aT²/4-aT²/8
= aT²/4
so, option d is correct
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