Question

A car with a velocity 12m/s takes 6s to come to rest when the brakes are applied. Find deceleration

Answer 1

Here,

Initial velocity = 12m/s

Final velocity = 0m/s ( car comes at rest)

A/q

Acceleration = v-u/t

Acceleration = 0-12/6

= -12/6

= -2 m/s2

Answer 2

Question:-

A car with a velocity 12m/s takes 6s to come to rest when the brakes are applied. Find deceleration.

To Find:-

• Find the deceleration of the car.

Given:-

• The car has a velocity of 12m/s and it applies brake for 6 seconds and car comes to rest.

Formulas:-

• v = u + at
• v² - u² = 2as
• s = ut + 1/2 at²

Solution:-

u = 12 m/s ; v = 0 ; t = 6 sec ; a = ?

We have to find the acceleration for that we can use the acceleration formula and also first equation of motion formula.

$\boxed{a \: = \: \frac{v - u}{t}}$

$a \: = \frac{0 \: - \: 12}{6}$

a = -12/6

a = -2 m/s²

∴ The deceleration of the car is -2 m/s².