Question

A car with a velocity of 54km/hr accelerate uniformly at the rate of 2m/s calculate the distance travelled from the place where acceleration began

Answer 1

let's first convert km/hr into m/s

54 km/hr : 15m/s

72 km/hr : 20m/s

Applying :

v^2-u^2=2aSv

2 −u 2 =2aS

20\times20-15\times15=2\times2\times S\\S=175/4=43.75 m20×20−15×15=2×2×S

S=175/4=43.75m