Question

: A car with initial velocity zero experiences a uniform acceleration of 7 m/s2 for the time interval t= 5s. Calculate its distance covered?​

Answer 1

Answer:

s=ut+1/2at^2

s=0*5+1/27*5^2

s=0+175/s=175/2

s=87.5m

Answer 2

To Find :-

• It's distance covered.

Solution :-

Given,

• Initial velocity $\bold{(u_0)}$ = 0 ms-¹
• Acceleration (a) = 7 ms-²
• Time interval (t) = 5 s

By using the Kinematic Equation, one can determine that,

$\red\bigstar$ $\bold{ s = u_0+ \frac{1}{2} \times at^2}$

[ Put the values ]

$\longrightarrow$ s = 0 × 5 + ¹/2 × 7 × 5²

$\longrightarrow$ s = 0 + 0.5 × 7 × 25

$\longrightarrow$ s = 3.5 × 25

$\longrightarrow$ s = 87.5 m $\green\bigstar$

Therefore

The distance covered by the car is 87.5 m.