Question

A car with mass 2000 kg moves with velocity 20 m/s on a friction surface. If the car takes
100 m to stop, determine the friction force.

Answer 1

Using the equation of motion v^2 = u^2 + 2as you can substitute the numbers in and rearrange for the acceleration, a, as follows: (0^-20^2)/2*100 = -2 ms^2.

therefore deceleration = 2 ms^2

using Newton’s second law F=ma and assuming that friction is the only resistive force acting on the car we find -F= 2000*-2 therefore frictional force F= 4000N

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